….It’s not as funny because the question had nothing to do with the length of the rope…it has to do with the forces acting on it. Its a problem of the guys strength vs. gravity.
The length of the rope on the grappling hook isn’t relevant here at all actually.
The rope could be 150 feet long, but if you can’t throw it upwards 20 feet you are screwed. Most grappling hooks are probably longer, as most mountains are over 20 feet tall. Furthermore, don’t people remove the packaging before going hiking in the mountains?
The correct answer (borrowing some lines from Koenigscat):
h(t) = -16t^2 – 32t + 5
h(0) = 5
h’(t) = -32t – 32
for t > 0, h’(t) < 0
Or in English…from the moment the grappling hook is released (t = 0) at 5 feet high, it drops like a rock. The real question is, why did you give us such a heavy grappling hook, teach?
{ 12 comments… read them below or add one }
If you are Rico Rodriguez , then the answer is yes.
Tooooooo fucking true! what is the point in these type of questions! of course it will say on the packaging! Thank you
I get the feeling this isn’t the first time he has used that answer.
True, but I don’t think that is what the teacher is looking for.
HEHEHE….
VERY FUNNY
What is the answer he writes, can’t read it very well.
God I hate math for that reason right there. When would I ever use that problem in normal everyday life? The freaking packaging would have the length.
….It’s not as funny because the question had nothing to do with the length of the rope…it has to do with the forces acting on it. Its a problem of the guys strength vs. gravity.
The length of the rope on the grappling hook isn’t relevant here at all actually.
The rope could be 150 feet long, but if you can’t throw it upwards 20 feet you are screwed. Most grappling hooks are probably longer, as most mountains are over 20 feet tall. Furthermore, don’t people remove the packaging before going hiking in the mountains?
answer: http://www.wolframalpha.com/input/?i=maximum+of+-16t^2+-+32t+%2B+5
that’s 21
h(t) = -16t^2 – 32t + 5
h’(t) = -32t – 32
-32t – 32 = 0
-32t = 32
-t = 1
t = -1
h(-1) = -16(-1)^2 – 32(-1) + 5 = 21
High enough to reach the ledge
its its its its its its its its its its it’s
The correct answer (borrowing some lines from Koenigscat):
h(t) = -16t^2 – 32t + 5
h(0) = 5
h’(t) = -32t – 32
for t > 0, h’(t) < 0
Or in English…from the moment the grappling hook is released (t = 0) at 5 feet high, it drops like a rock. The real question is, why did you give us such a heavy grappling hook, teach?